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EXCEL |
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Two-Sample Hypothesis Z-Test (Variances Known) |
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Perform a Two-Sample Z-Test: |
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Assumptions: |
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1. Independent Samples. |
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2. No assumption about the shape of either population is required. |
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3. Variances for both populations are known. |
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4. Both samples contain at least 30 observations. |
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The following are the grades of 30 students in two sections of a statistics class. |
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A |
B |
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1 |
Section 1 Grade |
Section 2 Grade |
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2 |
90 |
99 |
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3 |
89 |
98 |
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4 |
66 |
100 |
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5 |
77 |
100 |
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6 |
99.9 |
99.9 |
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7 |
66 |
100 |
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8 |
57 |
98 |
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9 |
44 |
44 |
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10 |
66 |
99 |
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11 |
78 |
33 |
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12 |
88 |
88 |
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13 |
99 |
99 |
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14 |
97 |
97 |
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15 |
100 |
100 |
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16 |
99 |
95 |
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17 |
99 |
59 |
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18 |
97 |
47.9 |
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19 |
88 |
100 |
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20 |
92 |
100 |
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21 |
93 |
28.2 |
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22 |
54 |
98 |
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23 |
68 |
86 |
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24 |
84 |
56 |
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25 |
91 |
28 |
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26 |
76 |
97 |
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27 |
73 |
55 |
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28 |
87 |
76 |
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29 |
92 |
89 |
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30 |
94 |
51 |
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31 |
38 |
43 |
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Enter the data; place the grades for section 1 in column A and the grades for section 2 in |
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column B. Variances are known to be 25 for each section. |
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Compare the grades of the two sections of a statistics class: |
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Perform a hypothesis test at the 5% significance level to determine if there exists a |
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significant difference in grades of the two sections. |
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Perform Hypothesis Test with EXCEL: |
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1. Enter the data into columns A and B. |
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2. Select Tools and Data Analysis. |
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3. Select Z-Test: Two-Sample for Means and click OK. |
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4. Input the following in the dialog box: |
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a. Input Variable 1 Range: A1:A31. |
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b. Input Variable 2 Range: B1:B31. |
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c. Hypothesized Mean Difference: 0. |
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d. Input Variable 1 Variance (known): 25 |
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e. Input Variable 2 Variance (known): 25 |
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f. Click on Labels (since you included the labels in your input range). |
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g. Alpha: 0.05. |
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h. Check Output Range and specify the range, if you would like the output on the same |
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spreadsheet. Output Range is A35. Choose a New Work Sheet Ply if you like a |
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new sheet. |
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i. Click OK and you will see the output below. |
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z-Test: Two Sample for Means |
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Section 1 Grade |
Section 2 Grade |
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Mean |
81.39666667 |
78.8 |
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Known Variance |
25 |
25 |
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Observations |
30 |
30 |
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Hypothesized Mean Difference |
0 |
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z |
2.011369351 |
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P(Z<=z) one-tail |
0.022143159 |
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z Critical one-tail |
1.644853476 |
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P(Z<=z) two-tail |
0.044286319 |
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z Critical two-tail |
1.959962787 |
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Interpret Your Results: |
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1. State the hypothesis: |
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H0: μ1 = μ2 |
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HA: μ1 ≠ μ2 |
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2. Level of Significance: α = 0.05 and we have a two-tailed test. |
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3. Determine Test Statistic: z = 2.011 |
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4. Decision Rule: Critical z-Value: Reject Ho if z > 1.96 or z< - 1.96. |
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5. Make a Decision: Reject Ho since 2.011 does fall into the rejection region. |
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6. Conclusion: There exists enough evidence at the 5% significance level to claim that there is |
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a significant difference in the grades of the two sections of statistics classes. |
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© copyright 2004 Elisabeth Knowlton